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#21
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Ed wrote: I believe what the original poster meant was that the occurance of a false positive is 1%. That would mean that after taking 12000 tests, 1% or 120 false positive results would be expected. If there were a total of 380 positives out of that same 12000, 120 would be false ones and the other 260 would be real. HTH Ed Yes. |
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#22
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On Sun, 30 Jul 2006 01:12:43 +0200, Montesquiou wrote:
In the 120 we have some Good Guys wrongly called cheaters, and some cheaters called Good Guys OK ? If the errors are random, then half of them are false negatives which would never be reported. So the probability of a false positive in a sample of 12000 is 60 or .005. |
#23
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CowPunk wrote:
Ed wrote: I believe what the original poster meant was that the occurance of a false positive is 1%. That would mean that after taking 12000 tests, 1% or 120 false positive results would be expected. If there were a total of 380 positives out of that same 12000, 120 would be false ones and the other 260 would be real. HTH Ed Yes. But you know see that the percentage of the false positives has to be independent of the number of the number of total positives, right? I mean, imagine you test 10000 subjects, where 10000 have done Tes. I.e. you get 10000 positives, and none of them is wrong. The percentage describes the probability of a positive being false, not the probability of any test producing a false positive. |
#24
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On Sun, 30 Jul 2006 14:35:23 +0200, Montesquiou wrote:
"CowPunk" a écrit dans le message de news: . com... 1% of 12000 = 120 120:380 ~ 1:3 Oh my friend !!! With all due respect if it is way they teach statistic in your country ... You are lost. However as I have many friends in the USA and I know they are not so ignorants in Math, I believe the problem is your. Since your original post you DECIDED that 1% of the test were wrong. So 1% of the 380 positive (that you DECIDED BY YOUR OWN) are wrong. 1% of 380 is 3.8. Turn your problem the way you want 1% is allway 1% and NEVER 1:3 (33.33 %) !! Oh my God, pls help me ! You do need help. If the probability of error is 1%, then there will be 120 errors in a sample of 12000. If the number of positives actually found is 380, then by chance slightly less than 1 in 3 are errors. There is also the probability of a false negative when the sample actually was dirty but the test failed to pick it up. Contrary to my previous post this does make the chance of a false positive .005 because you can only have a false negative if the sample was actually dirty and I hope that half the 12000 samples were not dirty. |
#25
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Ernst Noch wrote in :
CowPunk wrote: Ed wrote: I believe what the original poster meant was that the occurance of a false positive is 1%. That would mean that after taking 12000 tests, 1% or 120 false positive results would be expected. If there were a total of 380 positives out of that same 12000, 120 would be false ones and the other 260 would be real. HTH Ed Yes. But you know see that the percentage of the false positives has to be independent of the number of the number of total positives, right? I mean, imagine you test 10000 subjects, where 10000 have done Tes. I.e. you get 10000 positives, and none of them is wrong. The percentage describes the probability of a positive being false, not the probability of any test producing a false positive. The number of false positives is based on the number of tests performed. The percentage gives the number of false positives expected for every 100 tests performed. The percentage is not the probility of a positive being false. If 100 tests were done, then one would expect 1 negative sample to show up positive. Thus if you did 100 tests, and there was one positive, it is likely that this result is in error. If 65 of the 100 were positive, then (statistically) 64 were correct and 1 was a false positive. Ed |
#26
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#27
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#29
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Jack Hollis wrote: On 30 Jul 2006 08:47:16 -0700, wrote: Dear Bovine: First you have to define error. I'm just saying for the sake of argument that the 1% error represents: 0.1% false positive errors i.e. those for which no one can account, a function of the test itself. + 0.5% contamination errors + 0.4% lab technician erros 0.1 + 0.4 + 0.5 = 1% overall error actually positive and negative. real numbers a @12100 test performed 3.8% positive |
#30
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Ed wrote:
Ernst Noch wrote in : CowPunk wrote: Ed wrote: I believe what the original poster meant was that the occurance of a false positive is 1%. That would mean that after taking 12000 tests, 1% or 120 false positive results would be expected. If there were a total of 380 positives out of that same 12000, 120 would be false ones and the other 260 would be real. HTH Ed Yes. But you know see that the percentage of the false positives has to be independent of the number of the number of total positives, right? I mean, imagine you test 10000 subjects, where 10000 have done Tes. I.e. you get 10000 positives, and none of them is wrong. The percentage describes the probability of a positive being false, not the probability of any test producing a false positive. The number of false positives is based on the number of tests performed. The percentage gives the number of false positives expected for every 100 tests performed. The percentage is not the probility of a positive being false. If 100 tests were done, then one would expect 1 negative sample to show up positive. Thus if you did 100 tests, and there was one positive, it is likely that this result is in error. If 65 of the 100 were positive, then (statistically) 64 were correct and 1 was a false positive. Ed I was wrong above. I just forgot that stuff, so I looked it up, here's a good explanation: http://en.wikipedia.org/wiki/Binary_classification What I was thinking of is sensitivity and specificity. |
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