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Just what does a 60% chance of rain mean?
dgk writes:
On Wed, 5 Aug 2009 09:17:59 -0700, "Terry Neff" wrote: "dgk" wrote in message . .. Does it mean that somewhere within 100 miles of me there is a 60% chance of rain falling, or does it mean that there is a 60% chance that I'm going to get rained on (assumimg that I'm outside)? I'm not a big fan of biking in the rain, although being around 90F today I sort of am looking forward to it. I ran into a story about this a few months back and learned something new from it. Apparently it is intended to indicate neither the _percentage of different locations_ within the named area which are expected to get wet that day, nor the _percentage of time_ any given location might get wet on that day. Rather, it is intended to indicate the _percentage of different days_, each having the same atmospheric conditions, when rain will fall somewhere within the named area. And apparently then that means that on (100 minus _that percentage of days_) no rain will fall anywhere within that area. [...] Ok, so all it is telling me is that there is a 60% chance of rain somewhere in the area. Actually, it has dropped to 40%. I'm very likely not to get wet, at least by rain. I believe it means that there is a 60% chance of measurable rain at any given point in the forecast area (it's assumed that the probability is equal everywhere in the area). From http://www.srh.noaa.gov/ffc/html/pop.shtml : The "Probability of Precipitation" (PoP) describes the chance of precipitation occurring at any point you select in the area. How do forecasters arrive at this value? Mathematically, PoP is defined as follows: PoP = C x A where "C" = the confidence that precipitation will occur somewhere in the forecast area, and where "A" = the percent of the area that will receive measureable precipitation, if it occurs at all. So... in the case of the forecast above, if the forecaster knows precipitation is sure to occur ( confidence is 100% ), he/she is expressing how much of the area will receive measurable rain. ( PoP = "C" x "A" or "1" times ".4" which equals .4 or 40%.) But, most of the time, the forecaster is expressing a combination of degree of confidence and areal coverage. If the forecaster is only 50% sure that precipitation will occur, and expects that, if it does occur, it will produce measurable rain over about 80 percent of the area, the PoP (chance of rain) is 40%. ( PoP = .5 x .8 which equals .4 or 40%. ) In either event, the correct way to interpret the forecast is: there is a 40 percent chance that rain will occur at any given point in the area. |
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