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#91
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Warning: H*lm*t content
Euan Wrote: "Theo" == Theo Bekkers writes: Theo Resound wrote: And, importantly, it's only recently that we've been moving at greater than running speed. Hit the ground at 20kph and you're okelydokely. Hit the ground at 40kph and you're much more likely to break something important. Not always of course, but doubling impact speed is always going to skew your results more than a touch. Theo Err, if you fall off your bike you will hit the ground at Theo approx 20km/h regardless of the speed at which you are Theo travelling. This is the design spec of bike helmets. Should Theo you have a horizontal velocity of 40 km/h you will still hit Theo the ground at 20km/h. I don't think that's correct. When there are two or more velocities what we have a vectors. We have the horizontal component (40km/h) and the vertical component. The vector simplistically is the root of the sum of the horizontal squared and the vertical squared. For the cited figures that gives a velocity of 44km/h on point of impact. A combination of kinetic absorption and friction dissipates the velocity. -- Cheers | ~~ __@ Euan | ~~ _-\, Melbourne, Australia | ~ (*)/ (*) Why do you get in to vectors when you do not know what they mean? The vertical component of it, is what give you impact against th ground, that is what the helmet should absorb. The horizontal componen gives rotation, you could argue that the helmet makes that worse, sinc the radius of the helmet is bigger than the head. You could also argu that the friction of the helmet against the road is lower, and tha helps to minimise the rotation. It also gives road rash, where th helmet does help. Again, if your horizontal component is 50 km/h an you hit a boulder straight on, well, helmet or not, you die -- Claes |
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#92
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Warning: H*lm*t content
Claes Wrote: The MAJORITY of accidents, in Sweden at least, are single accidents. Th only force absorbed is head towards the ground. Lets assume head hit the ground at a VERTICAL speed of 20 km/h as stated before, an suddenly, the helmet makes sense. Vertical? I clipped a protruding building site stake and went straigh over the bars with half a twist. Landed flat. The impact was 98 horizontal. That's what cut the back of my head. Now, when I am crawling along on a stinking hot summer day, havin stripped of my gloves for the cooling, should I protect my hands wit my head? After all, my helmet will protect me -- aeek |
#93
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Warning: H*lm*t content
Euan wrote:
"ritcho" == ritcho writes: ritcho Euan Wrote: Bicycle helmets absorb kinetic energy (KE). The formula for KE is: KE = 1/2 * M * V^2 ritcho This doesn't smell right - surely it is the distribution of ritcho the energy of an impact through time and across an area that ritcho determine the likelihood of damage. You have shown that the ritcho distribution of energy through time is little changed, ritcho especially for higher speed impacts, but not shown that ritcho energy is dissipated across a wider area of the head. It's kinetic energy. Area is not a factor in kinetic energy. It's an absolute figure. A helmet has X kinetic energy absorption capacity. ritcho For example, a 20kg plate can be supported by balancing it ritcho on your head, but put a nail in the centre of the plate and ritcho you'll pierce a nice hole in your head if you try to balance ritcho it in the same way. This example says nothing about ritcho velocity, but something about the distribution of force... That's correct, force. That's different from kinetic energy and depending what you're trying to calculate there are many different equations. You're thinking of pressure. Pressure is force over an area. If you hit your head on the pavement without a helmet your head cracks open because a high pressure is applied to a small area of the skull, but with a helmet the force is spread over a larger area and the pressure is reduced, and that's why you only end up with a bit of a headache. Zoom Zoom |
#94
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Warning: H*lm*t content
aeek Wrote: Vertical? I clipped a protruding building site stake and went straigh over the bars with half a twist. Landed flat. The impact was 98 horizontal. That's what cut the back of my head. Now, when I am crawling along on a stinking hot summer day, havin stripped of my gloves for the cooling, should I protect my hands wit my head? After all, my helmet will protect me! Again, if you hit something at high speed, horizontal speed, the impac speed will be roughly the same as the speed that you are travelling Now, when you just plainly fall, or go over the hanldbars on a fla road, your horizontal speed will not be as bad as the vertical speed a which you hit the ground, that has got nothing to do with how fast yo go. And again, a single accident is not that interesting -- Claes |
#95
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Warning: H*lm*t content
Euan Wrote: "ritcho" == ritcho writes: ritcho Euan Wrote: Bicycle helmets absorb kinetic energy (KE). The formula for KE is: KE = 1/2 * M * V^2 ritcho This doesn't smell right - surely it is the distribution of ritcho the energy of an impact through time and across an area that ritcho determine the likelihood of damage. You have shown that the ritcho distribution of energy through time is little changed, ritcho especially for higher speed impacts, but not shown that ritcho energy is dissipated across a wider area of the head. It's kinetic energy. Area is not a factor in kinetic energy. It's an absolute figure. A helmet has X kinetic energy absorption capacity. ritcho For example, a 20kg plate can be supported by balancing it ritcho on your head, but put a nail in the centre of the plate and ritcho you'll pierce a nice hole in your head if you try to balance ritcho it in the same way. This example says nothing about ritcho velocity, but something about the distribution of force... That's correct, force. That's different from kinetic energy and depending what you're trying to calculate there are many different equations. -- Cheers | ~~ __@ Euan | ~~ _-\, Melbourne, Australia | ~ (*)/ (*) The point being that damage is a function of the rate at which energ is absorbed and the area over which it is absorbed. The helmet doesn' have to absorb all of the energy of an impact - it just has to sprea it around space and time. Ritc -- ritcho |
#96
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Warning: H*lm*t content
Euan wrote: "Resound" == Resound writes: Bicycle helmets absorb kinetic energy (KE). The formula for KE is: KE = 1/2 * M * V^2 Resound That does make a bit of difference, dunnit? I do wonder how Resound constant the energy dispersion of a helmet relative to Resound speed is though. Probably not a squared function though. No idea, I'm not an engineer. I've just got basic physics under my belt and I can remember some equations and Google what I can't :-) You also forget that forces work in directions. 35km/h horizontally is mostly irrelevant* when you fall down from 2m under the influence of gravity. A bike helmet won't do squat at 35km/h to dead stop, but that's not the point. Back to your sums, Euan * yes, rolling adds repeated impacts, all the more reason to have a helmet on ... |
#97
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Warning: H*lm*t content
Euan wrote: "ritcho" == ritcho writes: ritcho Euan Wrote: Bicycle helmets absorb kinetic energy (KE). The formula for KE is: KE = 1/2 * M * V^2 ritcho This doesn't smell right - surely it is the distribution of ritcho the energy of an impact through time and across an area that ritcho determine the likelihood of damage. You have shown that the ritcho distribution of energy through time is little changed, ritcho especially for higher speed impacts, but not shown that ritcho energy is dissipated across a wider area of the head. It's kinetic energy. Area is not a factor in kinetic energy. It's an absolute figure. A helmet has X kinetic energy absorption capacity. ritcho For example, a 20kg plate can be supported by balancing it ritcho on your head, but put a nail in the centre of the plate and ritcho you'll pierce a nice hole in your head if you try to balance ritcho it in the same way. This example says nothing about ritcho velocity, but something about the distribution of force... That's correct, force. That's different from kinetic energy and depending what you're trying to calculate there are many different equations. One of the advantages of a helmet (or any device designed to lessen point impacts) is that pressure (which does a lot of damage, eg nails cv dinner plates) is reduced. That square law you're thinking about wrt KE, well, pressure = force/area, and area is a square function also. The rest is left as an exercise to the reader. |
#98
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Warning: H*lm*t content
David Trudgett wrote: Option 1: Compulsory xyz Option 2: Refuse healthcare Unfortunately, both your options are unChristian. I am not a christian. This is aus.bicyles, religious argument really doesn't belong, eh? |
#99
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Warning: H*lm*t content
So if you don't like to wear a helmet don't wear one! hey it onl affects you and it's your decision to make and they can do terribl things to your hairstyle! Wrong My better half is an emergency staff specialist at one of the mai teaching hospitals in Sydney. If you get permanent brain damage you are fscked. You will be a burde on the community and your family for the rest of your life. The ta payers will be paying to suport you through your long rehab, if you ar able to be rehabilitated. This does happen!! She has seen numerous instances wear someone has completely smashe their helmet but they are OK. So it wont happen to you, it'll happen to someone else. You might b the someone else. Cheers Geof -- geoffs |
#100
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Warning: H*lm*t content
geoffs Wrote: She has seen numerous instances wear someone has completely smashe their helmet but they are OK. So it wont happen to you, it'll happen to someone else. You might b the someone else. so, in summer, I SHOULD protect my bare hands with my helmetted head -- aeek |
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